NEUTRON
.
A five loop pyramidal structure would
compound into quark sets as per fig 1. The double
positive quark pairs are a symmetrical impossibility. The
structure lacks any opposing double negative quark pairs.
This would make the particle subject to a great
distortion separating the two double positive quark pairs
and stretching the structure. The only possible solution
to this problem is an octahedral arrangement, which would
have to be a composition of two pyramid structures joined
at their bases. One would have to be generally positive,
meaning it would have to have 2 double positive quarks
and the other would have to be negative, meaning it would
have to have 2 double negative quarks.
fig.
1
But, this would
insert extra quarks into the already occupied 4 edges of
the “base”. Therefore, such a structure is
again an impossibility. Next option is a straightforward
octahedral structure fig 2.
fig.
2
Its unilateral
triangular planes would be subject to symmetric
distortion, because the quarks and antiquarks of opposite
loops meet across planes in alike polarity relationship.
This stretches the theoretical unilateral triangle sided
octahedron base equally in its plane. The angle of the
side pyramid edges relative to the base plane will
slightly close. The angle of the triangular planes will
be out of 3 x 60 deg. relationship and the octahedron
will flatten to a degree.
The degree of angular
distortion of crystalline structure of hydrogen atom can
be mathematically back related to the force, with which
the opposing fields of alike quarks across the triangular
planes repulse each other. This is when the octahedral
structure is in thermal state. There is no distortion
when the structure is in complete el. current state. When
the atom is in near el. current state, it may be prone to
disintegration into light and some emitted electrons.
The ratio of quark to
loop to particle segment remains the same as in the
nucleon #1, the proton. Here we have a set of 2 x 4 = 8
photon loops, which tie into 12 quark – antiquark
pairs. There are three spin segments per photon loop and
each quark pair has again 1/3 spin number.
The idea that a
hydrogen atom consists of a proton, a neutron and an
electron is unsupportable. The hydrogen atom is actually
a neutron, which may and may not support electrically
neutral valence bond, open or closed. Normally, two such
octahedrons joined at their apexes by a neutral valence
bond would make a diatomic molecule. Without any other
valence bond on the structure, we would have one electron
per two octahedrons (or as presented by the orthodoxy one
electron of a valence bond per two proton-neutron
nucleuses).
In geometrical
reality of the structuring, there will have to be another
open valence bond at each outer apex of a diatomic
molecule. When none of these apexes is tied to any other
molecules or atoms, its open valence bonds tie into a
single mixed polarity electric field around the
octahedral pair. The tension of the field bends the two
octahedrons or neutrons into a letter V and actually
tends to close into a second closed valence bond.
Single hydrogen atoms
can be induced into positive, as well as negative
ionization. There is no law or natural process, which
could prevent this. Mono-atomic hydrogen open valence
bond can be distorted in the same way an emitted electron
can. The orientation of the neutron pair relative to the
outside conditions (other matter) and orientation of the
hydrogen atom internal polarity in the gravitational
network and its vector of motion decides, whether the ion
is negative or positive. Polarity of induction from
outside will also decide the polarity of hydrogen atom or
molecule. The apparently externally non polarized open
valence bond will show an excess of either negative or
positive charge. The same goes for most molecules and
atoms.
The balanced, meaning
neutral charge of large conglomerate of atoms can be also
expressed in the form of a dipole magnetic field, rather
than a dipole charge.
This structuring is
probably the key to the solution of the difference
between H3 and He3 isotopes.
This solution, right
or wrong, still leaves the proton structure as the
smallest common denominator for nucleons. It also points
out that some photon loops may have to be removed from
the basic structures when these structures conglomerate
into larger atoms and that the internal loop geometric
relationship of nucleons may and often does change when
nuclear reactions take place. Unless the structuring is
developed to the order of transuraniums, there is no way
to know why large structures loose some photon train
loops, while disintegrating in fission.
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